(2⌈nbn⌉−1) a∑ u=1 (B1,u +B2,u), B1,u = 2⌈nbn⌉−(k2−k1)−1−u∑ i=1 B1,u,i, (B.23) B2,u =: 2⌈nbn⌉−(k2−k1)−1−u∑ i=1 B2,u,i. (B.24) and B1,u,i = E(Gj1,i,k2,uGj1,i,k2,0)K( i+u+k2−k1−⌈nbn⌉ nbn )K( i−⌈nbn⌉ nbn )) B2,u,i [...] Define for a = 1, 2 L̂σ̂ 3,a(u, t) = m̂a(u, t)− r̂3,a(u, t), Û σ̂ 3,a(u, t) = m̂a(u, t) + r̂3,a(u, t) where r̂3,a(u, t) = σ̂a(u, t) √ 2T σ̂ ⌊(1−α)B⌋√ nbn √ m′ n(2⌈nbn⌉ −m′ n) and T σ̂ ⌊(1−α)B⌋ is generated [...] respect to x ∈ R). For a proof of (B.8) we assume without loss of generality that mn is even so that m′ n = mn. For convenience, let ∑b i=a Zi = 0 if the indices a and b satisfy a > b. Given the data, it …

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Spot Rf Spot Rf B1b1 0/19 B2b1 0/14 B1b2 0/34 B2b2 0/17 B1b3 0/45 B2b3 0/31 B1b4 0/53 B2b4 0/38 B1b5 0/59 B2b5 0/51 B1b6 0/72 B2b6 0/59 B1b7 0/88 B2b7 0/74 B1b8 0/93 B2b8 0/88 - - B2b9 0/93 EXCLI Journal [...] bi ti on  Z on e  (m m ) * B.c er eu s B.a nt hr ac is B.p um ilu s S.a ur eu s S.e pid er m idi s L.m on oc yto ge ne s Str . P yo ge ne s P.a er ug ino sa E.c oli P.m ira bil is Br .m eli te ns is K.p [...] bi ti on  Z on e  (m m ) * B.c er eu s B.a nt hr ac is B.p um ilu s S.a ur eu s S.e pid er m idi s L.m on oc yto ge ne s Str . P yo ge ne s P.a er ug ino sa E.c oli P.m ira bil is Br .m eli te ns is K.p …